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codeforces #519 A A. Multiplication Table (暴力)

·385 字·1 分钟

A. Multiplication Table

time limit per test

1 second

memory limit per test

256 megabytes

input

standard input

output

standard output

Let’s consider a table consisting of n rows and n columns. The cell located at the intersection of i-th row and j-th column contains number i × j. The rows and columns are numbered starting from 1.

You are given a positive integer x. Your task is to count the number of cells in a table that contain number x.

Input

The single line contains numbers n and x (1 ≤ n ≤ 105, 1 ≤ x ≤ 109) – the size of the table and the number that we are looking for in the table.

Output

Print a single number: the number of times x occurs in the table.

Sample test(s)

input

10 5

output

2

input

6 12

output

4

input

5 13

output

0

Note

A table for the second sample test is given below. The occurrences of number 12 are marked bold.

我的内心是崩溃的。。。

20天没写代码。。。

然后这道谁题。。。竟然wa了两次。。。

其实思路是没有错的。。。

然后自作聪明得想优化。。。

把优化去掉就A了。。

慢慢恢复感觉==

哦,光扯了。

这道题很显然。。。x出现的话,在每一行只可能出现0次或1次。。

要同时满足 x%i==0 和 x/i<=n

 1/*******************************************************************
 2Author :111qqz
 3*******************************************************************/
 4
 5#include <algorithm>
 6#include <cstdio>
 7#include <iostream>
 8#include <cstring>
 9#include <string>
10#include <cmath>
11#include <map>
12#include <stack>
13#include <queue>
14#include <set>
15
16using namespace std;
17typedef long long LL;
18typedef unsigned long long ULL;
19const int inf = 0x7fffffff;
20int main()
21{
22    int n,x;
23    int ans=  0;
24    cin>>n>>x;
25    for ( int i = 1 ; i <= n ; i++)
26    {
27        if (x%i==0 && x/i<=n)
28        {
29            ans++;
30        }
31    }
32    cout<<ans<<endl;
33
34    return 0;
35}

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