codeforces 522 A. Reposts

http://codeforces.com/problemset/problem/522/A 题意:给定某条消息的传播路径。问最远传播的距离。。 思路:其实就是问树的深度。。直接dfs就行了。。

存的时候用map<string,vector > mp;的方式存即可。

/* ***********************************************
Author :111qqz
Created Time :2015年12月05日 星期六 16时41分41秒
File Name :code/cf/problem/522A.cpp
************************************************ */
 1#include <cstdio>
 2#include <cstring>
 3#include <iostream>
 4#include <algorithm>
 5#include <vector>
 6#include <queue>
 7#include <set>
 8#include <map>
 9#include <string>
10#include <cmath>
11#include <cstdlib>
12#include <ctime>
13#define fst first
14#define sec second
15#define lson l,m,rt<<1
16#define rson m+1,r,rt<<1|1
17#define ms(a,x) memset(a,x,sizeof(a))
18typedef long long LL;
 1using namespace std;
 2const double eps = 1E-8;
 3const int dx4[4]={1,0,0,-1};
 4const int dy4[4]={0,-1,1,0};
 5const int inf = 0x3f3f3f3f;
 6const int N=2E2+7;
 7map<string,vector<string> > mp;
 8map<string,bool>vis;
 9string from,to,nouse;
10int ans;
11int n;
 1void dfs(string cur,int depth)
 2{
 3//    cout<<"cur:"<<cur<<" depth:"<<depth<<endl;
 4    vis[cur] = true;
 5    ans = max(ans,depth);
 6    for ( int i = 0 ; i < mp[cur].size() ; i++)
 7    {
 8	string v = mp[cur][i];
 9	if (!vis[v])
10	    dfs(v,depth+1);
11    }
12}
 1string tran(string x)
 2{
 3    int len = x.length();
 4    for ( int i = 0 ; i < len ; i++)
 5    {
 6	if (x[i]>='A'&&x[i]<='Z')
 7	{
 8	    x[i] = char(x[i]+32);
 9	}
10    }
11    return x;
12}
13int main()
14{
15	#ifndef  ONLINE_JUDGE 
16	freopen("code/in.txt","r",stdin);
17  #endif
18	mp.clear();
19	scanf("%d",&n);
20//	getchar();
21	for ( int i = 0 ; i < n ; i++)
22	{
23	    cin>>to>>nouse>>from;
24	    to = tran(to);
25	    from = tran(from);
26//	    getchar();
27	//    cout<<"to:"<<to<<endl<<" nouse:"<<nouse<<endl<<" from:"<<from<<endl;
28	    mp[from].push_back(to);
29	}
30	ans = 1;
31	dfs("polycarp",1);
32	printf("%d\n",ans);
1  #ifndef ONLINE_JUDGE  
2  fclose(stdin);
3  #endif
4    return 0;
5}