uva 120 Stacks of Flapjacks
题意:给出一个长度为n的序列(无重复元素),询问经过多少次flip(i)操作,使得序列升序排列。定义flip(i)为将1到n-i+1的元素反转... 思路:先离散化,然后注意读入....
/* ***********************************************
Author :111qqz
Created Time :2016年01月25日 星期一 10时42分46秒
File Name :code/uva/120.cpp
************************************************ */
#include <cstdio>
#include <cstring>
#include <iostream>
#include <algorithm>
#include <vector>
#include <queue>
#include <set>
#include <map>
#include <string>
#include <cmath>
#include <cstdlib>
#include <ctime>
#define fst first
#define sec second
#define lson l,m,rt<<1
#define rson m+1,r,rt<<1|1
#define ms(a,x) memset(a,x,sizeof(a))
typedef long long LL;
#define pi pair < int ,int >
#define MP make_pair
using namespace std;
const double eps = 1E-8;
const int dx4[4]={1,0,0,-1};
const int dy4[4]={0,-1,1,0};
const int inf = 0x3f3f3f3f;
const int N=105;
int n;
int a[N];
string in;
struct node
{
int value;
int id;
}q[N];
int pos[N];
bool cmp1(node a,node b)
{
return a.value<b.value;
}
bool cmp2(node a,node b)
{
return a.id<b.id;
}
void flip2( int x)
{
for ( int i = 1 ; i <= x/2 ; i++)
{
swap(q[i].value,q[x+1-i].value);
}
}
void print( int n)
{
for ( int i = 1 ; i <= n ; i ++) printf(" %d ",q[i].value);
printf("\n");
}
void getpos( int n)
{
for ( int i = 1 ; i <= n ; i++)
{
pos[q[i].value] = i;
}
}
int main()
{
#ifndef ONLINE_JUDGE
freopen("code/in.txt","r",stdin);
#endif
while (getline(cin,in))
{
ms(pos,-1); //pos[i]表示数字i的位置
// cout<<"oriin:"<<in<<endl;
int p = in.find(' ');
int val;
int cnt = 0 ;
while (p!=-1)
{
string tmp = in.substr(0,p);
sscanf(tmp.c_str(),"%d",&val);
in.erase(0,p+1);
p = in.find(' ');
// cout<<"in:"<<in<<endl;
cnt++;
a[cnt] = val;
}
sscanf(in.c_str(),"%d",&val);
cnt++;
a[cnt]=val;
for ( int i = 1 ; i <= cnt ; i++) cout<<a[i]<<" ";
cout<<endl;
//hash
for ( int i = 1 ; i <= cnt ; i++)
{
q[i].value = a[i];
q[i].id = i ;
}
sort(q+1,q+cnt+1,cmp1);
int hashnum = 0;
for ( int i = 1 ; i <=cnt ; i++)
{
hashnum++;
q[i].value = hashnum;
}
sort(q+1,q+cnt+1,cmp2);
//check hash
// for ( int i =1 ; i <= cnt ; i++) cout<<"q[i].val:"<<q[i].value<<" ";
for ( int i = 1 ; i <= cnt ; i++)
{
pos[q[i].value] = i ;
}
// print(cnt);
for ( int i = cnt ; i >=1 ; i--)
{
if (pos[i]==i) continue;
if (pos[i]==1)
{
printf("%d ",cnt+1-i);
flip2(i);
// print(cnt);
getpos(cnt);
}
else
{
printf("%d ",cnt+1-pos[i]);
flip2(pos[i]);
// print(cnt);
getpos(cnt);
printf("%d ",cnt+1-i);
flip2(i);
// print(cnt);
getpos(cnt);
}
}
puts("0");
}
#ifndef ONLINE_JUDGE
fclose(stdin);
#endif
return 0;
}