uva 120 Stacks of Flapjacks
题意:给出一个长度为n的序列(无重复元素),询问经过多少次flip(i)操作,使得序列升序排列。定义flip(i)为将1到n-i+1的元素反转... 思路:先离散化,然后注意读入....
/* ***********************************************
Author :111qqz
Created Time :2016年01月25日 星期一 10时42分46秒
File Name :code/uva/120.cpp
************************************************ */
1#include <cstdio>
2#include <cstring>
3#include <iostream>
4#include <algorithm>
5#include <vector>
6#include <queue>
7#include <set>
8#include <map>
9#include <string>
10#include <cmath>
11#include <cstdlib>
12#include <ctime>
13#define fst first
14#define sec second
15#define lson l,m,rt<<1
16#define rson m+1,r,rt<<1|1
17#define ms(a,x) memset(a,x,sizeof(a))
18typedef long long LL;
19#define pi pair < int ,int >
20#define MP make_pair
1using namespace std;
2const double eps = 1E-8;
3const int dx4[4]={1,0,0,-1};
4const int dy4[4]={0,-1,1,0};
5const int inf = 0x3f3f3f3f;
6const int N=105;
7int n;
8int a[N];
9string in;
1struct node
2{
3 int value;
4 int id;
5}q[N];
6int pos[N];
7bool cmp1(node a,node b)
8{
9 return a.value<b.value;
10}
11bool cmp2(node a,node b)
12{
13 return a.id<b.id;
14}
1void flip2( int x)
2{
3 for ( int i = 1 ; i <= x/2 ; i++)
4 {
5 swap(q[i].value,q[x+1-i].value);
6 }
7}
1void print( int n)
2{
3 for ( int i = 1 ; i <= n ; i ++) printf(" %d ",q[i].value);
4 printf("\n");
5}
1void getpos( int n)
2{
3 for ( int i = 1 ; i <= n ; i++)
4 {
5 pos[q[i].value] = i;
6 }
7}
8int main()
9{
10 #ifndef ONLINE_JUDGE
11 freopen("code/in.txt","r",stdin);
12 #endif
1 while (getline(cin,in))
2 {
3 ms(pos,-1); //pos[i]表示数字i的位置
4 // cout<<"oriin:"<<in<<endl;
5 int p = in.find(' ');
6 int val;
7 int cnt = 0 ;
8 while (p!=-1)
9 {
1 string tmp = in.substr(0,p);
2 sscanf(tmp.c_str(),"%d",&val);
3 in.erase(0,p+1);
4 p = in.find(' ');
5 // cout<<"in:"<<in<<endl;
6 cnt++;
7 a[cnt] = val;
8 }
9 sscanf(in.c_str(),"%d",&val);
10 cnt++;
11 a[cnt]=val;
1 for ( int i = 1 ; i <= cnt ; i++) cout<<a[i]<<" ";
2 cout<<endl;
3 //hash
4 for ( int i = 1 ; i <= cnt ; i++)
5 {
6 q[i].value = a[i];
7 q[i].id = i ;
8 }
1 sort(q+1,q+cnt+1,cmp1);
2 int hashnum = 0;
3 for ( int i = 1 ; i <=cnt ; i++)
4 {
5 hashnum++;
6 q[i].value = hashnum;
7 }
8 sort(q+1,q+cnt+1,cmp2);
//check hash
// for ( int i =1 ; i <= cnt ; i++) cout<<"q[i].val:"<<q[i].value<<" ";
1 for ( int i = 1 ; i <= cnt ; i++)
2 {
3 pos[q[i].value] = i ;
4 }
1 // print(cnt);
2 for ( int i = cnt ; i >=1 ; i--)
3 {
4 if (pos[i]==i) continue;
5 if (pos[i]==1)
6 {
7 printf("%d ",cnt+1-i);
8 flip2(i);
9 // print(cnt);
10 getpos(cnt);
1 }
2 else
3 {
4 printf("%d ",cnt+1-pos[i]);
5 flip2(pos[i]);
6 // print(cnt);
7 getpos(cnt);
8 printf("%d ",cnt+1-i);
9 flip2(i);
10 // print(cnt);
11 getpos(cnt);
12 }
13 }
14 puts("0");
}
1 #ifndef ONLINE_JUDGE
2 fclose(stdin);
3 #endif
4 return 0;
5}