hdu 3790 最短路径问题 (spfa模板题)

hdu 3790 题目链接

题意:给出n个点m条无向边,每条边有一个距离和一个花费。给出s,t。问从s到t的最短距离以及最短距离时的最小花费。当有多个距离最短的方案时,选取花费最少的。

spfa学习链接

usetc 每周算法讲堂之spfa

先写几道题加深理解。

记得初始化。。。。。。

/* ***********************************************
Author :111qqz
Created Time :2016年05月21日 星期六 18时42分24秒
File Name :code/hdu/3790.cpp
************************************************ */
 1#include <cstdio>
 2#include <cstring>
 3#include <iostream>
 4#include <algorithm>
 5#include <vector>
 6#include <queue>
 7#include <set>
 8#include <map>
 9#include <string>
10#include <cmath>
11#include <cstdlib>
12#include <ctime>
13#define fst first
14#define sec second
15#define lson l,m,rt<<1
16#define rson m+1,r,rt<<1|1
17#define ms(a,x) memset(a,x,sizeof(a))
18typedef long long LL;
19#define pi pair < int ,int >
20#define MP make_pair
 1using namespace std;
 2const double eps = 1E-8;
 3const int dx4[4]={1,0,0,-1};
 4const int dy4[4]={0,-1,1,0};
 5const int inf = 0x3f3f3f3f;
 6const int N=1E3+7;
 7int n,m;
 8int d[N];
 9int p[N];
10bool inq[N];
11vector < pair<int,pair<int,int> > > edge[N];
int s,t;
1void init()
2{
3    ms(inq,false);
4    ms(d,0x3f);
5    ms(p,0x3f);
    for ( int i = 0 ; i <=n ; i++) edge[i].clear();
}
1void spfa()
2{
3    queue<int>q;
4    q.push(s);
5    d[s] = 0 ;
6    p[s] = 0;
7    inq[s]=true;
1    while (!q.empty())
2    {
3	int now = q.front();
4//	cout<<"now:"<<now<<endl;
5	q.pop();
6	inq[now] = false;
 1	int siz = edge[now].size();
 2	for ( int i = 0 ; i < siz ; i ++)
 3	{
 4	    int v = edge[now][i].fst;
 5	    int nd = edge[now][i].sec.fst;
 6	    int nw = edge[now][i].sec.sec;
 7	//    cout<<"v:"<<v<<" nd:"<<nd<<" nw:"<<nw<<endl;
 8	    if (d[v]>d[now]+nd||((d[v]==d[now]+nd)&&(p[v]>p[now]+nw)))
 9	    {
10		d[v] = d[now] + nd;
11		p[v] = p[now] + nw;
1		if (inq[v]) continue;
2		q.push(v);
3		inq[v] = true;
4	    }
5	}
6    }
1}
2int main()
3{
4	#ifndef  ONLINE_JUDGE 
5	freopen("code/in.txt","r",stdin);
6  #endif
 1	while (scanf("%d%d",&n,&m)!=EOF)
 2	{
 3	    if (n==0&&m==0) break;
 4	    init();
 5	    for ( int i = 1 ; i <= m ; i++)
 6	    {
 7		int u,v,d,w;
 8		scanf("%d%d%d%d",&u,&v,&d,&w);
 9		edge[u].push_back(MP(v,MP(d,w)));
10		edge[v].push_back(MP(u,MP(d,w)));
11	    }
	    scanf("%d%d",&s,&t);


	    spfa();

	    printf("%d %d\n",d[t],p[t]);
	}
1  #ifndef ONLINE_JUDGE  
2  fclose(stdin);
3  #endif
4    return 0;
5}