poj 1422 Air Raid (DAG的最小路径覆盖,匈牙利算法)
题意+思路:DAG的最小路径覆盖。。。匈牙利算法。。。poj 2594的低配版。。
/* ***********************************************
Author :111qqz
Created Time :2016年05月26日 星期四 20时24分15秒
File Name :code/poj/r2594.cpp
************************************************ */
1#include <cstdio>
2#include <cstring>
3#include <iostream>
4#include <algorithm>
5#include <vector>
6#include <queue>
7#include <set>
8#include <map>
9#include <string>
10#include <cmath>
11#include <cstdlib>
12#include <ctime>
13#define fst first
14#define sec second
15#define lson l,m,rt<<1
16#define rson m+1,r,rt<<1|1
17#define ms(a,x) memset(a,x,sizeof(a))
18typedef long long LL;
19#define pi pair < int ,int >
20#define MP make_pair
1using namespace std;
2const double eps = 1E-8;
3const int dx4[4]={1,0,0,-1};
4const int dy4[4]={0,-1,1,0};
5const int inf = 0x3f3f3f3f;
6const int N=505;
7int n,m;
8bool conc[N][N];
9bool vis[N];
10int link[N];
11void floyd()
12{
13 for ( int k = 1 ; k <= n ; k++)
14 for ( int i = 1 ; i <= n ; i++)
15 for ( int j = 1 ; j <= n ; j++)
16 if (conc[i][k]&&conc[k][j]) conc[i][j] = true;
17}
1bool dfs( int u)
2{
3 for ( int i = 1 ; i <= n ; i++)
4 {
5 if (conc[u][i])
6 {
7 if (vis[i]) continue;
8 vis[i] = true;
9 if (link[i]==-1||dfs(link[i]))
10 {
11 link[i] = u;
12 return true;
13 }
14 }
15 }
16 return false;
17}
18int hungary()
19{
20 int res = 0 ;
21 ms(link,-1);
22 for ( int i = 1 ; i <= n ; i++)
23 {
24 ms(vis,false);
25 if (dfs(i)) res++;
26 }
27 return res;
28}
29int main()
30{
31 #ifndef ONLINE_JUDGE
32 freopen("code/in.txt","r",stdin);
33 #endif
1 while (scanf("%d%d",&n,&m)!=EOF)
2 {
3 if (n==0&&m==0) break;
4 ms(conc,false);
5 for ( int i = 1 ; i <= m ; i++)
6 {
7 int u,v;
8 scanf("%d%d",&u,&v);
9 conc[u][v] = true;
10 }
1 floyd();
2 int ans = hungary();
3 printf("%d\n",n-ans);
}
1 #ifndef ONLINE_JUDGE
2 fclose(stdin);
3 #endif
4 return 0;
5}