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poj 1422 Air Raid (DAG的最小路径覆盖,匈牙利算法)

poj 1422题目链接

题意+思路:DAG的最小路径覆盖。。。匈牙利算法。。。poj 2594的低配版。。

  1/* ***********************************************
  2Author :111qqz
  3Created Time :2016年05月26日 星期四 20时24分15秒
  4File Name :code/poj/r2594.cpp
  5************************************************ */
  6
  7#include <cstdio>
  8#include <cstring>
  9#include <iostream>
 10#include <algorithm>
 11#include <vector>
 12#include <queue>
 13#include <set>
 14#include <map>
 15#include <string>
 16#include <cmath>
 17#include <cstdlib>
 18#include <ctime>
 19#define fst first
 20#define sec second
 21#define lson l,m,rt<<1
 22#define rson m+1,r,rt<<1|1
 23#define ms(a,x) memset(a,x,sizeof(a))
 24typedef long long LL;
 25#define pi pair < int ,int >
 26#define MP make_pair
 27
 28using namespace std;
 29const double eps = 1E-8;
 30const int dx4[4]={1,0,0,-1};
 31const int dy4[4]={0,-1,1,0};
 32const int inf = 0x3f3f3f3f;
 33const int N=505;
 34int n,m;
 35bool conc[N][N];
 36bool vis[N];
 37int link[N];
 38void floyd()
 39{
 40    for ( int k = 1 ; k <= n ; k++)
 41	for ( int i = 1 ; i <= n ; i++)
 42	    for ( int j = 1 ; j <= n ; j++)
 43		if (conc[i][k]&&conc[k][j]) conc[i][j] = true;
 44}
 45
 46
 47bool dfs( int u)
 48{
 49    for ( int i = 1 ; i <= n ; i++)
 50    {
 51	if (conc[u][i])
 52	{
 53	    if (vis[i]) continue;
 54	    vis[i] = true;
 55	    if (link[i]==-1||dfs(link[i]))
 56	    {
 57		link[i] = u;
 58		return true;
 59	    }
 60	}
 61    }
 62    return false;
 63}
 64int hungary()
 65{
 66    int res = 0 ;
 67    ms(link,-1);
 68    for ( int i = 1 ; i <= n ; i++)
 69    {
 70	ms(vis,false);
 71	if (dfs(i)) res++;
 72    }
 73    return res;
 74}
 75int main()
 76{
 77	#ifndef  ONLINE_JUDGE
 78	freopen("code/in.txt","r",stdin);
 79  #endif
 80
 81	while (scanf("%d%d",&n,&m)!=EOF)
 82	{
 83	    if (n==0&&m==0) break;
 84	    ms(conc,false);
 85	    for ( int i = 1 ; i <= m ; i++)
 86	    {
 87		int u,v;
 88		scanf("%d%d",&u,&v);
 89		conc[u][v] = true;
 90	    }
 91
 92	    floyd();
 93	    int ans = hungary();
 94	    printf("%d\n",n-ans);
 95
 96	}
 97
 98  #ifndef ONLINE_JUDGE
 99  fclose(stdin);
100  #endif
101    return 0;
102}

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poj 1274 The Perfect Stall (匈牙利算法)

poj 1274题目链接 裸的匈牙利。 1/* *********************************************** 2Author :111qqz 3Created Time :2016年05月25日 星期三 17时49分22秒 4File Name :code/poj/1274.cpp 5************************************************ */ 6 7#include <cstdio> 8#include <cstring> 9#include <iostream> 10#include <algorithm> 11#include <vector> 12#include <queue> 13#include <set> 14#include <map> 15#include <string> 16#include <cmath> 17#include <cstdlib> 18#include <ctime> 19#define fst first 20#define sec second 21#define lson l,m,rt<<1 22#define rson m+1,r,rt<<1|1 23#define ms(a,x) memset(a,x,sizeof(a)) 24typedef long long LL; 25#define pi pair < int ,int > 26#define MP make_pair 27 28using namespace std; 29const double eps = 1E-8; 30const int dx4[4]={1,0,0,-1}; 31const int dy4[4]={0,-1,1,0}; 32const int inf = 0x3f3f3f3f; 33const int N=405; 34int n,m; 35int head[N]; 36int cnt; 37int link[N]; 38bool vis[N]; 39struct Edge 40{ 41 int v; 42 int nxt; 43}edge[N*N]; 44void addedge(int u,int v) 45{ 46 edge[cnt].v = v; 47 edge[cnt].nxt = head[u]; 48 head[u] = cnt; 49 cnt++; 50} 51 52bool dfs( int u) 53{ 54 // cout<<"u:"<<u<<endl; 55 for ( int i = head[u] ; i!=-1 ; i = edge[i].nxt) 56 { 57 int v = edge[i].v; 58// cout<<"v:"<<v<<endl; 59 if (vis[v]) continue; 60 vis[v] = true; 61 62 if (link[v]==-1||dfs(link[v])) 63 { 64 link[v] = u; 65 return true; 66 } 67 } 68 return false; 69} 70int hung() 71{ 72 int res = 0 ; 73 ms(link,-1); 74 for ( int i = 1 ; i <= n ; i++) 75 { 76 ms(vis,false); 77 if (dfs(i)) res++; 78 } 79 80 return res; 81} 82int main() 83{ 84 #ifndef ONLINE_JUDGE 85 freopen("code/in.txt","r",stdin); 86 #endif 87 88 while (scanf("%d%d",&n,&m)!=EOF) 89 { 90 ms(head,-1); 91 cnt = 0 ; 92 93 for ( int i = 1 ; i <= n ; i++) 94 { 95 int num; 96 scanf("%d",&num); 97 while (num--) 98 { 99 int x; 100 scanf("%d",&x); 101 x = x + n; 102 addedge(i,x); 103 } 104 } 105 int ans = hung(); 106 printf("%d\n",ans); 107 } 108 109 #ifndef ONLINE_JUDGE 110 fclose(stdin); 111 #endif 112 return 0; 113}

uva 10986 Sending email (spfa)

·1 分钟
uva10986题目链接 题意:裸的spfa. 思路:模板,1A. 1/* *********************************************** 2Author :111qqz 3Created Time :2016年05月25日 星期三 03时25分27秒 4File Name :code/uva/10986.cpp 5************************************************ */ 6 7#include <cstdio> 8#include <cstring> 9#include <iostream> 10#include <algorithm> 11#include <vector> 12#include <queue> 13#include <set> 14#include <map> 15#include <string> 16#include <cmath> 17#include <cstdlib> 18#include <ctime> 19#define fst first 20#define sec second 21#define lson l,m,rt<<1 22#define rson m+1,r,rt<<1|1 23#define ms(a,x) memset(a,x,sizeof(a)) 24typedef long long LL; 25#define pi pair < int ,int > 26#define MP make_pair 27 28using namespace std; 29const double eps = 1E-8; 30const int dx4[4]={1,0,0,-1}; 31const int dy4[4]={0,-1,1,0}; 32const int inf = 0x3f3f3f3f; 33const int N=2E4+7; 34int n,m; 35int S,T; 36vector < pi > edge[N]; 37 38int d[N]; 39bool inq[N]; 40bool spfa( int s,int t) 41{ 42 ms(d,0x3f); 43 ms(inq,false); 44 queue<int>q; 45 q.push(s); 46 inq[s] = true; 47 d[s] = 0; 48 49 while (!q.empty()) 50 { 51 int u = q.front(); 52 q.pop(); 53 inq[u] = false; 54 55 int siz = edge[u].size(); 56 57 for ( int i = 0 ; i < siz ; i++) 58 { 59 int v = edge[u][i].fst; 60 if (d[v]>d[u] + edge[u][i].sec) 61 { 62 d[v] = d[u] + edge[u][i].sec; 63 if (inq[v]) continue; 64 inq[v] = true; 65 q.push(v); 66 } 67 } 68 } 69 return d[t]!=inf; 70} 71int main() 72{ 73 #ifndef ONLINE_JUDGE 74 freopen("code/in.txt","r",stdin); 75 #endif 76 ios::sync_with_stdio(false); 77 int TT; 78 cin>>TT; 79 int cas = 0 ; 80 while (TT--) 81 { 82 cin>>n>>m>>S>>T; 83 for ( int i = 0 ; i <= n ; i++) edge[i].clear(); 84 for ( int i = 1 ; i <= m ; i++) 85 { 86 int u,v,w; 87 cin>>u>>v>>w; 88 edge[u].push_back(make_pair(v,w)); 89 edge[v].push_back(make_pair(u,w)); 90 } 91 92 if (spfa(S,T)) 93 { 94 printf("Case #%d: %d\n",++cas,d[T]); 95 } 96 else 97 { 98 printf("Case #%d: unreachable\n",++cas); 99 } 100 101 } 102 103 #ifndef ONLINE_JUDGE 104 fclose(stdin); 105 #endif 106 return 0; 107}