poj 1470 Closest Common Ancestors (lca,rmq+dfs,读入技巧)
题意:求两点的lca. 思路:dfs+rmq. 读入技巧。 读入比较坑爹。。。 学会了一种新的读入技巧。
scanf("%2s",st);
表示读一个长度为2的字符串。。。读的时候会忽略各种空白字符。
/* ***********************************************
Author :111qqz
Created Time :2016年05月19日 星期四 15时44分12秒
File Name :code/poj/1470.cpp
************************************************ */
1#include <cstdio>
2#include <cstring>
3#include <iostream>
4#include <algorithm>
5#include <vector>
6#include <queue>
7#include <set>
8#include <map>
9#include <string>
10#include <cmath>
11#include <cstdlib>
12#include <ctime>
13#define fst first
14#define sec second
15#define lson l,m,rt<<1
16#define rson m+1,r,rt<<1|1
17#define ms(a,x) memset(a,x,sizeof(a))
18typedef long long LL;
19#define pi pair < int ,int >
20#define MP make_pair
1using namespace std;
2const double eps = 1E-8;
3const int dx4[4]={1,0,0,-1};
4const int dy4[4]={0,-1,1,0};
5const int inf = 0x3f3f3f3f;
6const int N=905;
7int n;
8vector <int> edge[N];
9int in[N];
10int E[2*N],R[2*N];
11int depth[2*N];
12int p;
13int dp[2*N][12];
14int cnt[N];
15void dfs( int u,int dep)
16{
17 p++;
18 E[p] = u ;
19 depth[p] = dep;
20 R[u] = p;
21 int siz = edge[u].size();
22 for ( int i = 0 ; i < siz ; i ++)
23 {
24 int v = edge[u][i];
1 dfs(v,dep+1);
2 p++;
3 E[p] = u;
4 depth[p] = dep;
5 }
6}
1int _min( int l,int r)
2{
3 if (depth[l]<depth[r]) return l;
4 return r;
5}
6void rmq_init()
7{
8 for ( int i = 1 ; i <=2*n+2 ; i++) dp[i][0] = i;
1 for ( int j = 1 ; (1<<j) <= 2*n+2 ; j++)
2 for ( int i = 1 ; i + (1<<j)-1 <= 2*n+2 ; i++)
3 dp[i][j] = _min(dp[i][j-1],dp[i+(1<<(j-1))][j-1]);
4}
1int rmq_min( int l,int r)
2{
3 if (l>r) swap(l,r);
4 int k = 0;
5 while (1<<(k+1) <= r-l+1) k++;
6 return _min(dp[l][k],dp[r-(1<<k)+1][k]);
7}
8int main()
9{
10 #ifndef ONLINE_JUDGE
11 freopen("code/in.txt","r",stdin);
12 #endif
1 while (scanf("%d",&n)!=EOF)
2 {
3 ms(in,0);
4 for ( int i = 1 ; i <= n ; i++) edge[i].clear();
5 for ( int i = 1 ; i <= n ; i++)
6 {
7 char ch[5];
8 int x,num;
9 scanf("%d%2s%d%1s",&x,ch,&num,ch);
10// cout<<"x:"<<x<<" num:"<<num<<endl;
1 for ( int i = 1 ; i <= num ; i++)
2 {
3 int y;
4 scanf("%d",&y);
5 edge[x].push_back(y);
6 in[y]++;
7// cout<<"y:"<<y<<endl;
8 }
9 }
1 int root ;
2 for ( int i = 1 ; i <= n ; i++) if (in[i]==0) root = i ;
3// cout<<"root:"<<root<<endl;
4 p = 0;
5 dfs(root,0);
6 rmq_init();
ms(cnt,0);
1 int q;
2 scanf("%d",&q);
3// cout<<"q:"<<q<<endl;
4 while (q--)
5 {
6 char ch[5];
7 int x,y;
8 scanf("%1s%d%d%1s",ch,&x,&y,ch);
9 int LCA = E[rmq_min(R[x],R[y])];
10// cout<<"x:"<<x<<" y:"<<y<<" LCA:"<<LCA<<endl;
11 cnt[LCA]++;
12 }
13// cout<<"n:"<<n<<endl;
14 for ( int i = 1 ; i <= n ; i++)
15 {
16// cout<<"cnt[i]:"<<cnt[i]<<endl;
17 if (cnt[i]==0) continue;
18 printf("%d:%d\n",i,cnt[i]);
19 }
20 }
1 #ifndef ONLINE_JUDGE
2 fclose(stdin);
3 #endif
4 return 0;
5}