zoj 3195 Design the city (lca,dfs+rmq)
zoj 3195题目链接 题意:求树上三点的最短距离。。。 思路:两两求,和除以2. 因为忘记初始化p=0..WA了将近两个小时。。。? 妈的智障。
/* ***********************************************
Author :111qqz
Created Time :2016年05月21日 星期六 14时44分39秒
File Name :code/zoj/3195.cpp
************************************************ */
1#include <cstdio>
2#include <cstring>
3#include <iostream>
4#include <algorithm>
5#include <vector>
6#include <queue>
7#include <set>
8#include <map>
9#include <string>
10#include <cmath>
11#include <cstdlib>
12#include <ctime>
13#define fst first
14#define sec second
15#define lson l,m,rt<<1
16#define rson m+1,r,rt<<1|1
17#define ms(a,x) memset(a,x,sizeof(a))
18typedef long long LL;
19#define pi pair < int ,int >
20#define MP make_pair
1using namespace std;
2const double eps = 1E-8;
3const int dx4[4]={1,0,0,-1};
4const int dy4[4]={0,-1,1,0};
5const int inf = 0x3f3f3f3f;
6const int N=5E4+7;
7int n,m;
8vector < pi > edge[N];
9int q;
10int in[N];
11int E[2*N],R[2*N],dis[N],depth[2*N];
12int p;
13int dp[2*N][20];
14void dfs( int u,int dep,int d,int pre)
15{
1 // cout<<"u:"<<u<<" dep:"<<dep<<" d:"<<d<<endl;
2 p++;
3 E[p] = u;
4 depth[p] = dep;
5 R[u] = p ;
6 dis[u] = d;
1 int siz = edge[u].size();
2 for ( int i = 0 ; i < siz ; i++)
3 {
4 int v = edge[u][i].fst;
5 if (v==pre) continue;
6 dfs(v,dep+1,d+edge[u][i].sec,u);
1 p++;
2 E[p] = u;
3 depth[p] = dep;
4 }
5}
1int _min( int l,int r)
2{
3 if (depth[l]<depth[r]) return l;
4 return r;
5}
6void rmq_init()
7{
8 for ( int i = 1 ; i <= 2*n+2 ; i++) dp[i][0] = i;
1 for ( int j = 1 ; (1<<j) <= 2*n+2 ; j++)
2 for ( int i = 1 ; i + (1<<j)-1 <= 2*n+2 ; i++)
3 dp[i][j] = _min(dp[i][j-1],dp[i+(1<<(j-1))][j-1]);
4}
1int rmq_min( int l,int r)
2{
3 if (l>r) swap(l,r);
4 int k = 0 ;
5 while (1<<(k+1)<=r-l+1) k++;
6 return _min(dp[l][k],dp[r-(1<<k)+1][k]);
7}
8int solve (int x,int y)
9{
10 int LCA = E[rmq_min(R[x],R[y])];
11 int res = dis[x] + dis[y] - 2 * dis[LCA];
12 return res;
13}
14int main()
15{
16 #ifndef ONLINE_JUDGE
17 freopen("code/in.txt","r",stdin);
18 #endif
1 ms(in,0);
2 bool ok = false;
3 while (~scanf("%d",&n)){
4 if (ok) puts("");
5 ok = true;
6 for ( int i = 0 ; i <= n ; i++) edge[i].clear();
7 for ( int i = 1 ; i <= n-1 ; i++)
8 {
9 int u,v,w;
10 scanf("%d%d%d",&u,&v,&w);
11 edge[u].push_back(make_pair(v,w));
12 edge[v].push_back(make_pair(u,w));
13 }
1 p = 0 ;
2 dfs(0,0,0,-1);
3 rmq_init();
1 scanf("%d",&q);
2 while (q--)
3 {
4 int x,y,z;
5 scanf("%d%d%d",&x,&y,&z);
6 int ans = solve(x,y)+solve(x,z)+solve(y,z);
7 printf("%d\n",ans/2);
8 }
9 }
1#ifndef ONLINE_JUDGE
2 fclose(stdin);
3#endif
4 return 0;
5}