whust 2016 warm up E||codeforces 689 A. Mike and Cellphone (模拟)

cf689A

思路：一个老式的电话键盘。。。。给出一个拨号的移动路径。。。问这个路径是否唯一。

思路：如果唯一就说明。。。不能平移。。。否则不唯一。。

平移可以上下左右。。所以先写4个常亮数组。。。标记平移后的结果。。。设置不合法位就可以了。。。

 

C++
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/* ***********************************************
Author :111qqz
Created Time :2016年07月18日 星期一 12时56分28秒
File Name :code/2016whust/E.cpp
************************************************ */
 
#include <cstdio>
#include <cstring>
#include <iostream>
#include <algorithm>
#include <vector>
#include <queue>
#include <set>
#include <map>
#include <string>
#include <cmath>
#include <cstdlib>
#include <ctime>
#define fst first
#define sec second
#define lson l,m,rt<<1
#define rson m+1,r,rt<<1|1
#define ms(a,x) memset(a,x,sizeof(a))
typedef long long LL;
#define pi pair < int ,int >
#define MP make_pair
 
using namespace std;
const double eps = 1E-8;
const int dx4[4]={1,0,0,-1};
const int dy4[4]={0,-1,1,0};
const int inf = 0x3f3f3f3f;
 
const int up[15]={8,-1,-1,-1,1,2,3,4,5,6};
const int down[15]={-1,4,5,6,7,8,9,-1,0,-1};
const int l[15]={-1,-1,1,2,-1,4,5,-1,7,8};
const int r[15]={-1,2,3,-1,5,6,-1,8,9,-1};
int n;
string st;
 
bool solve()
{
    bool flag = true;
    for ( int i = 0 ; i < n ; i++)
    {
        int x = st[i]-'0';
//        cout<<"x:"<<x<<" x+up[x]"<<x+up[x]<<endl;
        x = up[x];
        if (x==-1)
        {
            flag = false;
//            cout<<"uuuuu"<<endl;
            break;
        }
    }
    if (flag) return true;
 
    flag = true;
    for ( int i = 0 ; i < n ; i++)
    {
        int x = st[i]-'0';
        x = down[x];
        if (x==-1)
        {
            flag = false;
//            cout<<"ddd"<<endl;
            break;
        }
    }
    if (flag) return true;
 
    flag = true;
    for ( int i = 0 ; i  < n;  i++)
    {
        int x = st[i]-'0';
        x = l[x];        
        if (x==-1)
        {
            flag = false;
//            cout<<"lll"<<endl;
            break;
        }
    }
 
    if (flag) return true;
    flag = true;
 
    for ( int i =  0 ; i  < n ; i++)
    {
        int x = st[i]-'0';
        x = r[x];
        if (x==-1)
        {
            flag = false;
//            cout<<"rrr:::"<<endl;
            break;
        }
    }
    if (flag) return  true;
 
    return false;
    
 
}
int main()
{
        #ifndef  ONLINE_JUDGE
        freopen("code/in.txt","r",stdin);
  #endif
 
 
        cin>>n;
        cin>>st;
        if (!solve())
        {
            puts("YES");
        }
        else
        {
            puts("NO");
        }
        
        
 
  #ifndef ONLINE_JUDGE  
  fclose(stdin);
  #endif
    return 0;
}
 
 
 
 

 

作者： CrazyKK

ex-ACMer@hust，stackoverflow-engineer@sensetime

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