whust 2016 warm up E ||codeforces 689 B. Mike and Shortcuts (spfa)
题意:n点。。点i到点j的代价是|i-j|..给出n条近路。。。a[i]表示点i到a[i]的代价为1(注意近路不一定就近)
思路:一开始建边卡了一下。。。实际上只要连相邻的就好了。。。然后边表只开了2N蠢哭。。。实际上应该3M...因为连相邻的边是双向的。。。再加上近路的单向。。。然后spfa就好了。。。。
/* ***********************************************
Author :111qqz
Created Time :2016年07月18日 星期一 13时33分18秒
File Name :code/2016whust/F.cpp
************************************************ */
1#include <cstdio>
2#include <cstring>
3#include <iostream>
4#include <algorithm>
5#include <vector>
6#include <queue>
7#include <set>
8#include <map>
9#include <string>
10#include <cmath>
11#include <cstdlib>
12#include <ctime>
13#define fst first
14#define sec second
15#define lson l,m,rt<<1
16#define rson m+1,r,rt<<1|1
17#define ms(a,x) memset(a,x,sizeof(a))
18typedef long long LL;
19#define pi pair < int ,int >
20#define MP make_pair
1using namespace std;
2const double eps = 1E-8;
3const int dx4[4]={1,0,0,-1};
4const int dy4[4]={0,-1,1,0};
5const int inf = 0x3f3f3f3f;
6const int N=2E5+7;
7int n;
8int a[N];
9bool inq[N];
10int d[N];
11int head[N];
12int cnt;
1struct Edge
2{
3 int v;
4 int w;
5 int nxt;
6}edge[8*N];
1void addedge( int u,int v,int w)
2{
3 edge[cnt].v = v;
4 edge[cnt].w = w;
5 edge[cnt].nxt = head[u];
6 head[u] = cnt;
7 cnt++;
8}
9void init()
10{
11 ms(head,-1);
12 cnt = 0 ;
13}
14void spfa( int s)
15{
16 ms(inq,false);
17 ms(d,0x3f);
18 queue<int>q;
19 q.push(s);
20 inq[s] = true;
21 d[s] = 0;
1 while (!q.empty())
2 {
3 int u = q.front();
4//< cout<<"u:"<<u<<endl;
5 q.pop();
6 inq[u] = false;
1 for ( int i = head[u] ; i!=-1 ; i = edge[i].nxt)
2 {
3 int v = edge[i].v;
4 int w = edge[i].w;
5 if (d[v]>d[u]+w)
6 {
7 d[v] = d[u] + w;
8 if (inq[v]) continue;
9 inq[v] = true;
10 q.push(v);
11 }
12// if (a[u]==v&&d[v]>1)
13// {
14// d[v] = 1;
15// if (inq[v]) continue;
16// inq[v] = true;
17// q.push(v);
18// }
1 }
2 }
3}
4int main()
5{
6 #ifndef ONLINE_JUDGE
7 freopen("code/in.txt","r",stdin);
8 #endif
1 cin>>n;
2 init();
3 for ( int i = 1 ; i <= n ; i++)
4 {
5 scanf("%d",&a[i]);
6 if (a[i]!=i)
7 addedge(i,a[i],1);
8// addedge(1,i,i-1);
9// addedge(i,1,i-1);
10// else addedge(i,a[i],0);
11 }
12 for ( int i = 1; i <= n-1 ; i++)
13 {
14 addedge(i,i+1,1);
15 addedge(i+1,i,1);
16 }
spfa(1);
for ( int i = 1 ; i <= n ; i++) printf("%d ",d[i]);
1 #ifndef ONLINE_JUDGE
2 fclose(stdin);
3 #endif
4 return 0;
5}