poj 3080 Blue Jeans (n个字符串的最长公共子串,暴力+kmp)
题意:给出n个字符串(n<=10),字符串长度不超过70,问出现在全部n个字符串中的最长并且字典序最小的长度大于等于3的子串。
思路:数据范围很小。。。直接暴力枚举+kmp匹配一下。。。
/* ***********************************************
Author :111qqz
Created Time :2016年08月11日 星期四 01时29分02秒
File Name :code/poj/3080.cpp
************************************************ */
#include <cstdio>
#include <cstring>
#include <iostream>
#include <algorithm>
#include <vector>
#include <queue>
#include <stack>
#include <set>
#include <map>
#include <string>
#include <cmath>
#include <cstdlib>
#include <deque>
#include <ctime>
#define fst first
#define sec second
#define lson l,m,rt<<1
#define rson m+1,r,rt<<1|1
#define ms(a,x) memset(a,x,sizeof(a))
typedef long long LL;
#define pi pair < int ,int >
#define MP make_pair
using namespace std;
const double eps = 1E-8;
const int dx4[4]={1,0,0,-1};
const int dy4[4]={0,-1,1,0};
const int inf = 0x3f3f3f3f;
const int N=70;
int nxt[N];
string dna[15];
int n ;
void getnxt( string a)
{
int i = 0 ;
int j = -1;
int n = a.length();
nxt[0] = -1;
while (i<n)
if (j==-1||a[i]==a[j]) nxt[++i]=++j;
else j = nxt[j];
}
bool kmp(string a,string b)
{
int m = a.length();
int n = b.length();
getnxt(a);
int i = 0;
int j = 0;
while (i<n)
{
if (j==-1||a[j]==b[i]) i++,j++;
else j=nxt[j];
if (j==m) return true;
}
return false;
}
int main()
{
#ifndef ONLINE_JUDGE
freopen("code/in.txt","r",stdin);
#endif
int T;
ios::sync_with_stdio(false);
cin>>T;
while (T--)
{
cin>>n;
for ( int i = 1 ; i <= n ; i++) cin>>dna[i];
string ans="";
int len = dna[1].length();
//cout<<"len:"<<len<<endl;
for ( int i = 0 ; i < len ; i++)
for ( int j = 1 ; i+j-1 < len ;j++)
{
bool match = true;
string tmp = dna[1].substr(i,j);
// cout<<"tmp:"<<tmp<<endl;
for ( int k = 2 ; k <= n; k++)
if (!kmp(tmp,dna[k]))
{
match = false;
break;
}
if (match)
{
// cout<<"ccc"<<endl;
if (tmp.length()>ans.length())
ans = tmp;
else if (tmp.length()==ans.length()&&tmp<ans)
ans = tmp;
}
}
if (ans.length()<3)
cout<<"no significant commonalities"<<endl;
else
cout<<ans<<endl;
}
#ifndef ONLINE_JUDGE
fclose(stdin);
#endif
return 0;
}