whust 2016 #1 H - Pair: normal and paranormal
其实就是括号匹配的模型。。用栈即可。。被我写挂好几发。。该死该死。。。
/* ***********************************************
Author :111qqz
Created Time :2016年08月07日 星期日 17时34分13秒
File Name :code/whust2016/#1/HH.cpp
************************************************ */
1#include <cstdio>
2#include <cstring>
3#include <iostream>
1#include <algorithm>
2#include <vector>
3#include <queue>
4#include <stack>
5#include <set>
6#include <map>
7#include <string>
8#include <cmath>
9#include <cstdlib>
10#include <deque>
11#include <ctime>
12#include <cctype>
13#define fst first
14#define sec second
15#define lson l,m,rt<<1
16#define rson m+1,r,rt<<1|1
17#define ms(a,x) memset(a,x,sizeof(a))
18typedef long long LL;
19#define pi pair < int ,int >
20#define MP make_pair
1using namespace std;
2const double eps = 1E-8;
3const int dx4[4]={1,0,0,-1};
4const int dy4[4]={0,-1,1,0};
5const int inf = 0x3f3f3f3f;
6const int N=1E4+7;
7char st[N];
8int s[N];
9int n;
10int plow[N];
11int pup[N];
12int ans[N];
13stack<int>stk;
1bool ok(int x, int y)
2{
3 // cout<<"x:"<<x<<" y:"<<y<<endl;
4 if (plow[x]>0&&pup[y]>0)
5 {
6 ans[pup[y]] = plow[x];
7 return true;
8 }
9 if (plow[y]>0&&pup[x]>0)
10 {
11 ans[pup[x]] = plow[y];
12 return true;
13 }
14 return false;
15}
16int main()
17{
18 #ifndef ONLINE_JUDGE
19 freopen("code/in.txt","r",stdin);
20 #endif
1 cin>>n>>st;
2 n*=2;
3 int cntA = 0 ;
4 int cnta = 0 ;
5 ms(pup,0);
6 ms(plow,0);
7 for ( int i = 0 ; i < n ; i++)
8 {
9 if (st[i]>='a'&&st[i]<='z')
10 {
11 cnta++;
12 plow[i] = cnta;
13 }
14 else
15 {
16 cntA++;
17 pup[i] = cntA;
18 }
19 }
20// for ( int i = 0 ; i < n ; i++) cout<<"plow[i]:"<<plow[i]<<" pup[i]:"<<pup[i]<<endl;
21 for ( int i = 0 ; i < n ; i++)
22 {
23 st[i] = toupper(st[i]);
24 }
25// cout<<"st:"<<st<<endl;
26 ms(ans,-1);
27 while (!stk.empty()) stk.pop();
28 stk.push(0);
29 for ( int i = 1 ; i < n ; i++)
30 {
31 while (!stk.empty()&&st[stk.top()]==st[i]&&ok(stk.top(),i)&&i<n)
32 {
33 stk.pop();
34 i++;
35 }
36 stk.push(i);
37 }
38 for ( int i = 1 ; i <= n/2 ; i++)
39 {
40 if (ans[i]==-1)
41 {
42 puts("Impossible");
43 return 0;
44 }
45 }
46 for ( int i = 1 ; i < n/2 ; i++) printf("%d ",ans[i]);
47 printf("%d\n",ans[n/2]);
1 #ifndef ONLINE_JUDGE
2 fclose(stdin);
3 #endif
4 return 0;
5}