hdu 2444 The Accomodation of Students (交叉染色法+匈牙利算法)
题意:判断一个有向图是否是二分图,是的话求最大匹配数。
思路:交叉染色判二分图,是的话跑遍匈牙利即可。1A.
1/* ***********************************************
2Author :111qqz
3Created Time :2016年09月01日 星期四 14时24分36秒
4File Name :code/hdu/2444.cpp
5************************************************ */
6#include <cstdio>
7#include <cstring>
8#include <iostream>
9#include <algorithm>
10#include <vector>
11#include <queue>
12#include <set>
13#include <map>
14#include <string>
15#include <cmath>
16#include <cstdlib>
17#include <ctime>
18#define fst first
19#define sec second
20#define lson l,m,rt<<1
21#define rson m+1,r,rt<<1|1
22#define ms(a,x) memset(a,x,sizeof(a))
23typedef long long LL;
24#define pi pair < int ,int >
25#define MP make_pair
26using namespace std;
27const double eps = 1E-8;
28const int dx4[4]={1,0,0,-1};
29const int dy4[4]={0,-1,1,0};
30const int inf = 0x3f3f3f3f;
31const int N=205;
32int n,m;
33vector<int>edge[N];
34int col[N];
35int link[N];
36bool vis[N];
37void init()
38{
39 for ( int i = 0 ; i <= n ; i++) edge[i].clear();
40 ms(col,-1);
41}
42bool dfs( int u,int x)
43{
44 col[u] = x;
45 int siz = edge[u].size();
46 for ( int i = 0 ; i < siz; i++)
47 {
48 int v = edge[u][i];
49 if (col[v]==1-x) continue;
50 if (col[v]==x) return false;
51 if (!dfs(v,1-x)) return false;
52 }
53 return true;
54}
55bool solve()
56{
57 for ( int i = 1 ; i <= n ; i++) if (col[i]==-1) if (!dfs(i,0)) return false;
58 return true;
59}
60bool Find( int u)
61{
62 int siz = edge[u].size();
63 for ( int i = 0 ; i < siz; i ++)
64 {
65 int v = edge[u][i];
66 if (vis[v]) continue;
67 vis[v] = true;
68 if (link[v]==-1||Find(link[v]))
69 {
70 link[v] = u;
71 return true;
72 }
73 }
74 return false;
75}
76int hung( int n)
77{
78 int ans = 0 ;
79 ms(link,-1);
80 for ( int i = 1 ; i <= n ; i++)
81 {
82 ms(vis,false);
83 if (Find(i)) ans++;
84 }
85 return ans;
86}
87int main()
88{
89 #ifndef ONLINE_JUDGE
90 freopen("code/in.txt","r",stdin);
91 #endif
92 while (~scanf("%d %d",&n,&m))
93 {
94 init();
95 for ( int i = 1 ; i <= m ; i++)
96 {
97 int u,v;
98 scanf("%d%d",&u,&v);
99 edge[u].push_back(v);
100 }
101 if (!solve())
102 {
103 puts("No");
104 }
105 else
106 {
107 int ans = hung(n);
108 printf("%d\n",ans);
109 }
110 }
111 #ifndef ONLINE_JUDGE
112 fclose(stdin);
113 #endif
114 return 0;
115}