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16/10/4 01:57

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codeforces

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codeforces #375 C. Polycarp at the Radio (贪心)

题目链接

题意：给出n,m，n个数，对其中的一些数进行修改，要求1..m中出现次数最少的数最大，输出这个最少的数最大是多少，以及修改的次数。

思路：最小的数最多出现n/m次。

竟然因为排序后下标变乱不知所措40分钟。。。我也是醉了。。。

C++
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/* ***********************************************
Author :111qqz
Created Time :2016年10月03日 星期一 19时29分52秒
File Name :code/cf/#375/C.cpp
************************************************ */
 
#include <cstdio>
#include <cstring>
#include <iostream>
#include <algorithm>
#include <vector>
#include <queue>
#include <set>
#include <deque>
#include <map>
#include <string>
#include <cmath>
#include <cstdlib>
#include <bitset>
#define fst first
#define sec second
#define lson l,m,rt<<1
#define rson m+1,r,rt<<1|1
#define ms(a,x) memset(a,x,sizeof(a))
typedef long long LL;
#define pi pair < int ,int >
#define MP make_pair
 
using namespace std;
const double eps = 1E-8;
const int dx4[4]={1,0,0,-1};
const int dy4[4]={0,-1,1,0};
const int inf = 0x3f3f3f3f;
const int N=2005;
int n,m;
int a[N];
struct node
{
    int id;
    int val;
    bool operator < (node b)const
    {
        return val<b.val;
    }
}cnt[N];
map<int,int>mp;
int main()
{
        #ifndef  ONLINE_JUDGE
        freopen("code/in.txt","r",stdin);
  #endif
        cin>>n>>m;
        ms(cnt,0);
        int C = 0 ;
        for ( int i = 1 ; i <= n ; i++)
        {
            cin>>a[i];
            if (a[i]<=m)
            {
                cnt[a[i]].val++;
            }else C++;
        }
        for ( int i = 1 ; i <= m ; i++) cnt[i].id = i ;
        int num = n/m;
        sort(cnt+1,cnt+m+1);
        for ( int i = 1 ; i <= m ; i++) mp[cnt[i].id] = i;
        int head = 1;
        int ans = 0 ;
        for ( int i = 1 ; i <= n ; i++)
        {
            if (a[i]>m&&C>n-m*num)
            {
                ans++;
                C--;
                cnt[head].val++;
                a[i] = cnt[head].id;
                if (cnt[head].val==num) head++;
            }else if (cnt[mp[a[i]]].val>num&&cnt[head].val<num)
                    {
                        ans++;
                        cnt[mp[a[i]]].val--;
                        cnt[head].val++;
                        a[i] = cnt[head].id;
                        if (cnt[head].val==num) head++;
 
                    }
        }
        printf("%d %d\n",num,ans);
        for ( int i = 1; i <= n ; i++) printf("%d ",a[i]);
 
  #ifndef ONLINE_JUDGE  
  fclose(stdin);
  #endif
    return 0;
}
 
 
 
 

 

 

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