leetcode 34. Search for a Range (二分,找到一段值为tar的区间)

Given an array of integers sorted in ascending order, find the starting and ending position of a given target value.

Your algorithm’s runtime complexity must be in the order of O(log n).

If the target is not found in the array, return [-1, -1].

For example,
Given [5, 7, 7, 8, 8, 10] and target value 8,
return [3, 4].

 

思路:二分。。。

我好像根本不会二分啊???

二分查找

 

 

 

作者: CrazyKK

ex-ACMer@hust,stackoverflow-engineer@sensetime

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