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以前用的办法太老土啦
看到一个since C++11的方法，我觉得比较优雅
1 #include <iostream>
2 #include <chrono>
3 //#include <ratio>
4 #include <thread>
5
6 void f()
7 {
8 std::this_thread::sleep_for(std::chrono::seconds(1));
9 }
10
11 int main()
12 {
13 auto t1 = std::chrono::high_resolution_clock::now();
14 f();
15 auto t2 = std::chrono::high_resolution_clock::now();
16
17 // floating-point duration: no duration_cast needed
18 std::chrono::duration<double, std::milli> fp_ms = t2 - t1;
19
20 // integral duration: requires duration_cast
21 auto int_ms = std::chrono::duration_cast<std::chrono::milliseconds>(t2 - t1);
22
23 // converting integral duration to integral duration of shorter divisible time unit:
24 // no duration_cast needed
25 std::chrono::duration<long, std::micro> int_usec = int_ms;
26
27 std::cout << "f() took " << fp_ms.count() << " ms, "
28 << "or " << int_ms.count() << " whole milliseconds "
29 << "(which is " << int_usec.count() << " whole microseconds)" << std::endl;
30 }