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Given n non-negative integers a1, a2, …, an, where each represents a point at coordinate (i, ai). n vertical lines are drawn such that the two endpoints of line i is at (i, ai) and (i, 0). Find two lines, which together with x-axis forms a container, such that the container contains the most water.
Note: You may not slant the container and n is at least 2.
题意：n条竖直的线段 (i,0)->(i,a[i]),从中选2条，和x轴共同组成一个开口的容器，问容器的最大面积。
思路：一开始想错了，以为是最大连续矩形面积…还在想leetcode竟然考单调栈？？？
然而实际上只取两个线段，中间的线段有没有，长度，都是无所谓的。
因此two pointer就好了。。。
1/* ***********************************************
2Author :111qqz
3Created Time :2017年04月13日 星期四 18时06分42秒
4File Name :11.cpp
5 ************************************************ */
6class Solution {
7
8 public:
9
10 int maxArea(vector<int>& height) {
11 int res = 0 ;
12 int n = height.size();
13 int head = 0 ;
14 int tail = n-1;
15 while (head<tail)
16 {
17 int h = min(height[head],height[tail]);
18 res = max(res,(tail-head)*h);
19 while (head<tail&&height[head]<=h) head++;
20 while (head<tail&&height[tail]<=h) tail--;
21 }
22 return res;
23
24
25 }
26
27};