<?xml version="1.0" encoding="utf-8" standalone="yes"?><rss version="2.0" xmlns:atom="http://www.w3.org/2005/Atom"><channel><title>容斥原理 on 111qqz's blog</title><link>https://111qqz.com/en/tags/%E5%AE%B9%E6%96%A5%E5%8E%9F%E7%90%86/</link><description>Recent content in 容斥原理 on 111qqz's blog</description><generator>Hugo -- gohugo.io</generator><language>en</language><copyright>© 2015-2026 111qqz</copyright><lastBuildDate>Tue, 08 Mar 2016 08:56:54 +0000</lastBuildDate><atom:link href="https://111qqz.com/en/tags/%E5%AE%B9%E6%96%A5%E5%8E%9F%E7%90%86/index.xml" rel="self" type="application/rss+xml"/><item><title>codeforces #345 div 2 C. Watchmen (容斥)</title><link>https://111qqz.com/en/post/acm-icpc/2016/2016-03-08-codeforces-345-div-2-c-watchmen-e5aeb9e696a5/</link><pubDate>Tue, 08 Mar 2016 08:56:54 +0000</pubDate><guid>https://111qqz.com/en/post/acm-icpc/2016/2016-03-08-codeforces-345-div-2-c-watchmen-e5aeb9e696a5/</guid><description>&lt;p&gt;&lt;a href="http://codeforces.com/contest/651/problem/C" target="_blank" rel="noreferrer"&gt;题目链接&lt;/a&gt;
题意：求曼哈顿距离和平方根距离相等的点的对数？
思路：化简发现是绝对值乘积等于0，容斥搞搞。&lt;/p&gt;</description></item><item><title>hdu 3929 Big Coefficients (递归形式的容斥原理+lucas定理的结论)</title><link>https://111qqz.com/en/post/acm-icpc/2016/2016-03-03-hdu3929/</link><pubDate>Thu, 03 Mar 2016 11:50:32 +0000</pubDate><guid>https://111qqz.com/en/post/acm-icpc/2016/2016-03-03-hdu3929/</guid><description>&lt;p&gt;题意：F(x) = (1+x)^a1 + (1+x)^a2 + … + (1+x)^am，求系数是奇数的项的个数。
思路：&lt;a href="http://blog.csdn.net/qian99/article/details/22692443" target="_blank" rel="noreferrer"&gt;解题报告&lt;/a&gt; 涉及到的由lucas定理得到的推论的证明&lt;a href="http://blog.csdn.net/qian99/article/details/22691571" target="_blank" rel="noreferrer"&gt;lucas定理证明&lt;/a&gt; 以及这篇理解里有递归形式的容斥定理的一般写法。。&lt;a href="http://www.acmerblog.com/hdu-3929-big-coefficients-6931.html" target="_blank" rel="noreferrer"&gt;递归形式的容斥定理&lt;/a&gt;&lt;/p&gt;</description></item><item><title>hdu 1796 How many integers can you find (容斥原理)</title><link>https://111qqz.com/en/post/acm-icpc/2016/2016-02-29-hdu1796/</link><pubDate>Mon, 29 Feb 2016 12:00:53 +0000</pubDate><guid>https://111qqz.com/en/post/acm-icpc/2016/2016-02-29-hdu1796/</guid><description>&lt;p&gt;&lt;a href="http://acm.hdu.edu.cn/showproblem.php?pid=1796" target="_blank" rel="noreferrer"&gt;hdu1796&lt;/a&gt;
题意：给出n（&amp;lt;=2^31）以及m(&amp;lt;=10)个元素组成的无重复元素集合，集合元素&lt;strong&gt;0&amp;lt;=a[i]&amp;lt;=20&lt;/strong&gt;,问有多少个小于n的数能至少被集合中的一个元素整除。&lt;/p&gt;</description></item><item><title>hdu 4336 Card Collector (2012多校 #4) （容斥原理模板题）</title><link>https://111qqz.com/en/post/acm-icpc/2016/2016-02-29-hdu4336/</link><pubDate>Mon, 29 Feb 2016 11:00:49 +0000</pubDate><guid>https://111qqz.com/en/post/acm-icpc/2016/2016-02-29-hdu4336/</guid><description>&lt;p&gt;&lt;a href="http://acm.hdu.edu.cn/showproblem.php?pid=4336" target="_blank" rel="noreferrer"&gt;http://acm.hdu.edu.cn/showproblem.php?pid=4336&lt;/a&gt;&lt;/p&gt;
&lt;p&gt;题意：有n种卡片，买一包干脆面得到第i种卡片的概率是p[i],每包干脆面最多有一张卡片，问收集齐所有卡片要买的干脆面的包数的数学期望。&lt;/p&gt;</description></item><item><title>hdu 5213 lucky （莫队算法）</title><link>https://111qqz.com/en/post/acm-icpc/2016/2016-02-15-hdu5213/</link><pubDate>Mon, 15 Feb 2016 08:58:30 +0000</pubDate><guid>https://111qqz.com/en/post/acm-icpc/2016/2016-02-15-hdu5213/</guid><description>&lt;p&gt;&lt;a href="http://acm.hdu.edu.cn/showproblem.php?pid=5213" target="_blank" rel="noreferrer"&gt;http://acm.hdu.edu.cn/showproblem.php?pid=5213&lt;/a&gt;
题意：n个数，m个查询，每个查询由4个数l1,r1,l2,r2构成，询问分别从[l1,r1]和[l2,r2]中各取一个数，和为给定的常数k的方案数。&lt;/p&gt;</description></item></channel></rss>