<?xml version="1.0" encoding="utf-8" standalone="yes"?><rss version="2.0" xmlns:atom="http://www.w3.org/2005/Atom"><channel><title>最大连续区间和 on 111qqz's blog</title><link>https://111qqz.com/en/tags/%E6%9C%80%E5%A4%A7%E8%BF%9E%E7%BB%AD%E5%8C%BA%E9%97%B4%E5%92%8C/</link><description>Recent content in 最大连续区间和 on 111qqz's blog</description><generator>Hugo -- gohugo.io</generator><language>en</language><copyright>© 2015-2026 111qqz</copyright><lastBuildDate>Thu, 15 Sep 2016 21:51:33 +0000</lastBuildDate><atom:link href="https://111qqz.com/en/tags/%E6%9C%80%E5%A4%A7%E8%BF%9E%E7%BB%AD%E5%8C%BA%E9%97%B4%E5%92%8C/index.xml" rel="self" type="application/rss+xml"/><item><title>BZOJ 1756: Vijos1083 小白逛公园　 （线段树维护单点修改区间查询最大子段和）</title><link>https://111qqz.com/en/post/acm-icpc/2016/2016-09-15-bzoj-1756/</link><pubDate>Thu, 15 Sep 2016 21:51:33 +0000</pubDate><guid>https://111qqz.com/en/post/acm-icpc/2016/2016-09-15-bzoj-1756/</guid><description>&lt;h2 class="relative group"&gt;1756: Vijos1083 小白逛公园
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&lt;p&gt;Time Limit: 10 Sec  Memory Limit: 64 MB
Submit: 1078  Solved: 353
[&lt;a href="http://www.lydsy.com/JudgeOnline/submitpage.php?id=1756" target="_blank" rel="noreferrer"&gt;Submit&lt;/a&gt;][&lt;a href="http://www.lydsy.com/JudgeOnline/problemstatus.php?id=1756" target="_blank" rel="noreferrer"&gt;Status&lt;/a&gt;][&lt;a href="http://www.lydsy.com/JudgeOnline/bbs.php?id=1756" target="_blank" rel="noreferrer"&gt;Discuss&lt;/a&gt;]&lt;/p&gt;</description></item><item><title>hit oj 2687 Candy (线段树动态维护最大连续子段)</title><link>https://111qqz.com/en/post/acm-icpc/2016/2016-09-15-hit-oj-2687-candy/</link><pubDate>Thu, 15 Sep 2016 21:04:48 +0000</pubDate><guid>https://111qqz.com/en/post/acm-icpc/2016/2016-09-15-hit-oj-2687-candy/</guid><description>&lt;p&gt;&lt;a href="http://acm.hit.edu.cn/hoj/problem/view?id=2687" target="_blank" rel="noreferrer"&gt;题目链接&lt;/a&gt;&lt;/p&gt;
&lt;p&gt;题意：给出n个数,m个修改，每次修改后询问整个区间的最大连续子段。&lt;/p&gt;</description></item><item><title>codeforces #327 A. Flipping Game</title><link>https://111qqz.com/en/post/acm-icpc/2015/2015-12-25-cf327a/</link><pubDate>Fri, 25 Dec 2015 13:53:06 +0000</pubDate><guid>https://111qqz.com/en/post/acm-icpc/2015/2015-12-25-cf327a/</guid><description>&lt;p&gt;&lt;a href="http://codeforces.com/contest/327/problem/A" target="_blank" rel="noreferrer"&gt;http://codeforces.com/contest/327/problem/A&lt;/a&gt;
题意：给定一段序列，只由0,1组成。要求选一段非空区间，做翻转操作（0变1,1变0），问变完之后1最多能有多少。
思路：最后的1个个数=初始的1的个数+变换区间的0的个数-变换区间的1的个数。初始的是常数。那么我们只要找到某一个区间内，0的个数-1的个数有最大值即可。如果a[i]==0的时候令b[i]=1，否则b[i]=0,那就是经典了最大连续区间和的问题了。dp的思想o(n)可以解决。&lt;/p&gt;</description></item></channel></rss>