<?xml version="1.0" encoding="utf-8" standalone="yes"?><rss version="2.0" xmlns:atom="http://www.w3.org/2005/Atom"><channel><title>矩阵快速幂 on 111qqz's blog</title><link>https://111qqz.com/en/tags/%E7%9F%A9%E9%98%B5%E5%BF%AB%E9%80%9F%E5%B9%82/</link><description>Recent content in 矩阵快速幂 on 111qqz's blog</description><generator>Hugo -- gohugo.io</generator><language>en</language><copyright>© 2015-2026 111qqz</copyright><lastBuildDate>Tue, 10 Oct 2017 10:19:55 +0000</lastBuildDate><atom:link href="https://111qqz.com/en/tags/%E7%9F%A9%E9%98%B5%E5%BF%AB%E9%80%9F%E5%B9%82/index.xml" rel="self" type="application/rss+xml"/><item><title>hdu 5950 Recursive sequence (构造矩阵，快速幂)</title><link>https://111qqz.com/en/post/acm-icpc/2017/2017-10-10-hdu-5950/</link><pubDate>Tue, 10 Oct 2017 10:19:55 +0000</pubDate><guid>https://111qqz.com/en/post/acm-icpc/2017/2017-10-10-hdu-5950/</guid><description>&lt;p&gt;&lt;a href="http://acm.split.hdu.edu.cn/showproblem.php?pid=5950" target="_blank" rel="noreferrer"&gt;题目链接&lt;/a&gt;&lt;/p&gt;

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&lt;p&gt;给f[1],f[2],n,f[i] = 2*f[i-2] + f[i-1] + i^4,求f[n]的值。&lt;/p&gt;</description></item><item><title>uva 10870 - Recurrences (矩阵加速线性递推式)</title><link>https://111qqz.com/en/post/acm-icpc/2017/2017-09-30-uva-10870/</link><pubDate>Sat, 30 Sep 2017 20:35:55 +0000</pubDate><guid>https://111qqz.com/en/post/acm-icpc/2017/2017-09-30-uva-10870/</guid><description>&lt;p&gt;&lt;a href="https://uva.onlinejudge.org/index.php?option=com_onlinejudge&amp;amp;Itemid=8&amp;amp;page=show_problem&amp;amp;problem=1811" target="_blank" rel="noreferrer"&gt;uva10870题目链接&lt;/a&gt;&lt;/p&gt;

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&lt;p&gt;f(n) = a1f(n − 1) + a2f(n − 2) + a3f(n − 3) + . . . + adf(n − d), for n &amp;gt; d&lt;/p&gt;</description></item><item><title>hdu 4990 Reading comprehension (构造矩阵，快速幂)</title><link>https://111qqz.com/en/post/acm-icpc/2017/2017-09-30-hdu-4990/</link><pubDate>Sat, 30 Sep 2017 11:38:05 +0000</pubDate><guid>https://111qqz.com/en/post/acm-icpc/2017/2017-09-30-hdu-4990/</guid><description>&lt;p&gt;&lt;a href="http://acm.hdu.edu.cn/showproblem.php?pid=4990" target="_blank" rel="noreferrer"&gt;题目链接&lt;/a&gt;&lt;/p&gt;

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&lt;p&gt;给出了一段程序，程序实际算的是f[n] = (f[n-1] + n%2)%m的值，其中f[1]=1,给出n,m(1E9)，问f[n]&lt;/p&gt;</description></item><item><title>hdu 5015 233 Matrix (构造矩阵，快速幂)</title><link>https://111qqz.com/en/post/acm-icpc/2017/2017-09-30-hdu-5015/</link><pubDate>Sat, 30 Sep 2017 10:54:07 +0000</pubDate><guid>https://111qqz.com/en/post/acm-icpc/2017/2017-09-30-hdu-5015/</guid><description>&lt;p&gt;&lt;a href="http://acm.hdu.edu.cn/showproblem.php?pid=5015" target="_blank" rel="noreferrer"&gt;hdu5015题目链接&lt;/a&gt;&lt;/p&gt;

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&lt;p&gt;给出矩阵的构造规则： a[0][j] (j&amp;gt;=1) 分别为233,2333,23333&amp;hellip;.给出a[i][0] (i&amp;gt;=1)，对于其余的i,j,a[i][j]=a[i-1][j] + a[i][j-1]&lt;/p&gt;</description></item><item><title>hdu 4549 M斐波那契数列 (矩阵快速幂+费马小定理+指数循环节)</title><link>https://111qqz.com/en/post/acm-icpc/2016/2016-10-26-hdu4549/</link><pubDate>Wed, 26 Oct 2016 09:12:43 +0000</pubDate><guid>https://111qqz.com/en/post/acm-icpc/2016/2016-10-26-hdu4549/</guid><description>&lt;p&gt;题意：M斐波那契数列F[n]是一种整数数列，它的定义如下：&lt;/p&gt;
&lt;p&gt;F[0] = a
F[1] = b
F[n] = F[n-1] * F[n-2] ( n &amp;gt; 1 )&lt;/p&gt;</description></item></channel></rss>