<?xml version="1.0" encoding="utf-8" standalone="yes"?><rss version="2.0" xmlns:atom="http://www.w3.org/2005/Atom"><channel><title>结论题 on 111qqz's blog</title><link>https://111qqz.com/en/tags/%E7%BB%93%E8%AE%BA%E9%A2%98/</link><description>Recent content in 结论题 on 111qqz's blog</description><generator>Hugo -- gohugo.io</generator><language>en</language><copyright>© 2015-2026 111qqz</copyright><lastBuildDate>Mon, 06 Nov 2017 11:09:10 +0000</lastBuildDate><atom:link href="https://111qqz.com/en/tags/%E7%BB%93%E8%AE%BA%E9%A2%98/index.xml" rel="self" type="application/rss+xml"/><item><title>hdu 6048 | 2017 Multi-University Training Contest - Team 2 D Puzzle (结论题)</title><link>https://111qqz.com/en/post/acm-icpc/2017/2017-11-06-hdu-6048/</link><pubDate>Mon, 06 Nov 2017 11:09:10 +0000</pubDate><guid>https://111qqz.com/en/post/acm-icpc/2017/2017-11-06-hdu-6048/</guid><description>&lt;p&gt;&lt;a href="http://acm.hdu.edu.cn/showproblem.php?pid=6048" target="_blank" rel="noreferrer"&gt;http://acm.hdu.edu.cn/showproblem.php?pid=6048&lt;/a&gt;&lt;/p&gt;

&lt;h1 class="relative group"&gt;题意：
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 &lt;a class="text-primary-300 dark:text-neutral-700 !no-underline" href="#%e9%a2%98%e6%84%8f" aria-label="Anchor"&gt;#&lt;/a&gt;
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&lt;p&gt;有 n * m - 1 个数，每次选择第 1,p + 1,p * 2 + 1…..
的顺序选择数，&lt;strong&gt;先按左到右，再按从上到下的顺序&lt;/strong&gt;填入n * m 的格子，空格子可以和相邻的数字交换位置，问最后能否在格子中形成 1~ n * m - 1的数按从左到右，从上到下的顺序。&lt;/p&gt;</description></item></channel></rss>