Max Angle **Time Limit: 4000/2000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 678 Accepted Submission(s): 238 ** Problem Description Given many points in a plane, two players are playing an interesting game. Player1 selects one point A as the vertex of an angle. Then player2 selects …

Transmitters **Time Limit:** 1000MS **Memory Limit:** 10000K **Total Submissions:** 4817 **Accepted:** 2576 Description In a wireless network with multiple transmitters sending on the same frequencies, it is often a requirement that signals don't overlap, or at least that they don't conflict. One way of …

20190211update:工作的时候看同事ocr的代码，发现有一段就是极角排序orz...所以说算法还是有用的... 先介绍几种极角排序： 1.利用叉积的正负来作cmp.(即是按逆时针排序).此题就是用这种方法 bool cmp(const point &a, const point &b)//逆时针排序 { point origin; origin.x = origin.y = 0; return cross(origin,b,origin,a) < 0; } 2.利用complex的内建函数。 #include #define x real() #define y imag() #include …